大神运用java写代码 java写代码的思路
求大神用Java编写出这个程序，要有具体代码，万分感激，定采纳
按照你的要求编写的JavaGUI程序如下：
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import java.awt.GridLayout;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JPanel;
import javax.swing.JTextField;
public class HH extends JFrame implements ActionListener{
JPanel jp1=new JPanel();
JPanel jp2=new JPanel();
JPanel jp3=new JPanel();
JTextField jtf=new JTextField(20);
JButton jb1=new JButton("显示");
JButton jb2=new JButton("清除");
HH(){
jb1.addActionListener(this);
jb2.addActionListener(this);
jp1.setLayout(new GridLayout(2,1));
jp3.add(jtf);
jp2.add(jb1);jp2.add(jb2);
jp1.add(jp3);jp1.add(jp2);
getContentPane().add(jp1);
setSize(300, 120);
setLocationRelativeTo(null);
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
setVisible(true);
}
@Override
public void actionPerformed(ActionEvent e) {
if(e.getSource()==jb1){
jtf.setText("java程序设计");
}
if(e.getSource()==jb2){
jtf.setText("");
}
}
public static void main(String[] args) {
new HH();
}
}
急，求大神帮我用JAvA写下下面这两道题的代码！！！！！！！！！！！
1）for:
import javax.swing.*;
public class moren {
public static void main(String agrs[]){
int i=0,n=0,s=1;
n=Integer.parseInt(JOptionPane.showInputDialog("输入N的值："));
if (0 == n)
s=1;
else
for (i=1;i=n;i++)
s*=i;
JOptionPane.showMessageDialog(null,+n+" 的阶乘为："+s,"阶乘计算器",JOptionPane.PLAIN_MESSAGE);
}
}
2)while:
import javax.swing.*;
public class moren {
public static void main(String agrs[]){
int i=1,n=0,s=1;
n=Integer.parseInt(JOptionPane.showInputDialog("输入N的值："));
if (0 == n)
s=1;
else
while(i=n)
{
s*=i;
i++;
}
JOptionPane.showMessageDialog(null,+n+" 的阶乘为："+s,"阶乘计算器",JOptionPane.PLAIN_MESSAGE);
}
}
3)do-while:
import javax.swing.*;
public class moren {
public static void main(String agrs[]){
int i=1,n=0,s=1;
n=Integer.parseInt(JOptionPane.showInputDialog("输入N的值："));
if (0 == n)
s=1;
else
do{
s*=i;
i++;
}while(i=n);
JOptionPane.showMessageDialog(null,+n+" 的阶乘为："+s,"阶乘计算器",JOptionPane.PLAIN_MESSAGE);
}
}
2、import javax.swing.*;
public interface Area{ //定义接口
public abstract double getArea();
}
class Ellipse implements Area{ //定义类
double r1,r2; // 定义两个半径
public Ellipse(double a, double b){ //构造方法
r1=a; r2=b;
}
public double getArea(){
double mj=Math.PI*r1*r2;
return mj;
}
public static void main(String[] args) {
double r1=0,r2=0;
r1=Float.parseFloat(JOptionPane.showInputDialog("输入长半径a："));
r2=Float.parseFloat(JOptionPane.showInputDialog("输入短半径b："));
Ellipse e1=new Ellipse(r1,r2);
JOptionPane.showMessageDialog(null,"此椭圆的面积为："+e1.getArea(),"椭圆面积计算器",JOptionPane.PLAIN_MESSAGE);
}
}
求助大神如何用Java写出这两个题目的代码？
第一题
package baidu;
public class Student {
protected String name;
protected int age;
public Student(String name, int age) {
this.name = name;
this.age = age;
}
public void show(){
System.out.println("name = " + name);
System.out.println("age = " + age);
}
}
---------------------------------
package baidu;
public class Undergraduate extends Student {
private String degree;
public Undergraduate(String name, int age, String degree) {
super(name, age);
this.degree = degree;
}
public void show(){
System.out.println("name = " + name);
System.out.println("age = " + age);
System.out.println("degree = " + degree);
}
}
------------------------
package baidu;
public class TestRun {
public static void main(String[] args) {
Student s = new Student("singi",12);
s.show();
Undergraduate ug = new Undergraduate("lily",23,"本科");
ug.show();
}
}
输出:
name = singi
age = 12
name = lily
age = 23
degree = 本科
第二题:
package baidu;
public class Man {
String name;
public Man(String name) {
this.name = name;
}
public void business(){
System.out.println("在方法内输出谈生意");
}
}
----------------
package baidu;
public class SuperMan extends Man {
String name;
public SuperMan(String name, String name1) {
super(name);
this.name = name1;
}
@Override
public void business() {
System.out.println("在方法内输出谈几个亿的大单子");
}
public void fly(){
System.out.println("在方法内输出超人不会飞");
}
}
------------------
package baidu;
public class TestMan {
public static void main(String[] args) {
Man m = new Man("singi");
System.out.println(m.name);
m.business();
SuperMan sm = new SuperMan("lily","xiaoming");
System.out.println(sm.name);
sm.business();
sm.fly();
}
}
输出:
singi
在方法内输出谈生意
xiaoming
在方法内输出谈几个亿的大单子
在方法内输出超人不会飞
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